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<math>a_n < \frac{1}{n}</math>
 
<math>a_n < \frac{1}{n}</math>
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[[User:Idryg|Idryg]] 14:51, 28 October 2008 (UTC)

Revision as of 10:51, 28 October 2008

Okay, so the problem is:

$ a_n = \frac{n!}{n^n} $

And, it hints to compare this with $ \frac{1}{n} $.

I don't get really how to compare these two.. I mean, I can see that the denominator of $ a_n $ will grow much faster than the numerator.

I'm guessing the limit approaches 0 as n approaches infinity, but I'm not sure how to mathematically show that

$ a_n < \frac{1}{n} $

Idryg 14:51, 28 October 2008 (UTC)

Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva