Difference between revisions of "Page 569, Problem 15 MA181Fall2008bell" - Rhea
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Revision as of 12:19, 19 October 2008
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Latest revision as of 12:21, 19 October 2008
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This one looks pretty easy, but I keep getting the wrong answer. Here's the problem.
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<math>\int_{0}^{2Pi}\sqrt{\frac{1-\cos{x}}{2}}dx</math>
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Obviously, <math>\frac{1-\cos{x}}{2} = \sin^2{\frac{x}{2}}</math>
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So, the integral should then look like:
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<math>\int_{0}^{2Pi}\sin{\frac{x}{2}}dx</math>
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Integrated, it comes out to:
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<math>[-2\cos{\frac{x}{2}}]_{0}^{2Pi}</math>
Latest revision as of 12:21, 19 October 2008
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