(New page: Alright, so: f(x) = e^g(x) and g(x) = t/(1+t^4) integrated from 2 to x. by the chain rule, f'(x) = g'(x)*e^g(x), correct? I just can't figure out what g'(x) would be.. what do you do...) |
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[[User:Idryg|Idryg]] 21:57, 6 October 2008 (UTC) | [[User:Idryg|Idryg]] 21:57, 6 October 2008 (UTC) | ||
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| + | Oh alright, I got it. g'(x) must just be x/(1+x^4), because I got the answer right. 2/17. [[User:Idryg|Idryg]] 22:05, 6 October 2008 (UTC) | ||
Latest revision as of 18:05, 6 October 2008
Alright, so:
f(x) = e^g(x)
and
g(x) = t/(1+t^4) integrated from 2 to x.
by the chain rule, f'(x) = g'(x)*e^g(x), correct?
I just can't figure out what g'(x) would be.. what do you do with the limits of integration when you take the derivative of a definite integral?
In other words, where does the 2 and x go? would g'(x) just be x/(1+x^4)?
I'm not sure. I probably shouldn't have waited until the night before it was due to start doing it haha
Idryg 21:57, 6 October 2008 (UTC)
Oh alright, I got it. g'(x) must just be x/(1+x^4), because I got the answer right. 2/17. Idryg 22:05, 6 October 2008 (UTC)
