(New page: == Problem 14 == <math>\text{Let } f\in C_c^{\infty}(R^n) \text{ be radial. Show that } \widehat{f} \text{ is also radial.}</math> ---- Note that f being radial implies that for some <...)
 
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Which gives precisely that <math>\widehat{f}</math> is radial.
 
Which gives precisely that <math>\widehat{f}</math> is radial.
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Written by Nicholas Stull

Revision as of 11:16, 27 July 2009

Problem 14

$ \text{Let } f\in C_c^{\infty}(R^n) \text{ be radial. Show that } \widehat{f} \text{ is also radial.} $


Note that f being radial implies that for some $ f^* $, $ f(x) = f^*(|x|) $ for every $ x\in R^n $

$ \widehat{f}\left(\xi e^{\imath \theta}\right) = \int_{R^n} f^*(|x|) e^{-\imath <x,\xi e^{\imath \theta}>} dx $

$ = \int_{R^n} f^*(|x|) e^{-\imath <x e^{-\imath \theta},\xi>} dx $

Now use a change of variables, namely $ x e^{-\imath \theta} = x $, and since this change of variables is given by a rotation (i.e. an orthogonal transformation with Jacobian 1)

$ = \int_{R^n} f^*(|x e^{-\imath \theta}|) e^{-\imath <x, \xi>} dx $

But recall that $ |x e^{-\imath \theta}| = |x| $, so:

$ = \int_{R^n} f^*(|x|) e^{-\imath <x,\xi>} dx = \widehat{f}(\xi) $

Which gives precisely that $ \widehat{f} $ is radial.

Written by Nicholas Stull

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood