(New page: X~Exp(1) f<sub>X</sub>(x)= k*e^(-k*x) Pr[X>x]= 1-F<sub>X</sub> (x)= e^(-k*x) say we know X>t What is Pr[X>x+t|X>t] We think it is Pr[X>x] Pr[X>x+t|X>t] = Pr[{X>t} {X>x+t}] / Pr[X>t] ...)
(No difference)

Revision as of 05:59, 15 October 2008

X~Exp(1)

fX(x)= k*e^(-k*x)

Pr[X>x]= 1-FX (x)= e^(-k*x)

say we know X>t

What is Pr[X>x+t|X>t]

We think it is Pr[X>x]

Pr[X>x+t|X>t] = Pr[{X>t} {X>x+t}] / Pr[X>t] = Pr[X>x+t] / Pr[X>t] = e^(-k*(x+t)) / e^(-k*t) = e(-k*t) = Pr[X>x]

Alumni Liaison

Recent Math PhD now doing a post-doctorate at UC Riverside.

Kuei-Nuan Lin