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[[Karen Shen|Karen's Solution]] | [[Karen Shen|Karen's Solution]] | ||
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| + | Karen's solution for part a is correct, but for part b I don't agree. There was nothing that said he threw in the lowest he could, although that would be smart. He could throw in either a nickel or a dime for anything 5 cents and under, thus there are two ways to pay. Then for anything 10 and under there are three, he could throw nickel nickel, nickel dime, or just a dime. Other than that I agree with Karen. --[[User:Kfox|-Kristen]] 21:39, 4 March 2009 (UTC) | ||
Latest revision as of 17:39, 4 March 2009
Karen's solution for part a is correct, but for part b I don't agree. There was nothing that said he threw in the lowest he could, although that would be smart. He could throw in either a nickel or a dime for anything 5 cents and under, thus there are two ways to pay. Then for anything 10 and under there are three, he could throw nickel nickel, nickel dime, or just a dime. Other than that I agree with Karen. ---Kristen 21:39, 4 March 2009 (UTC)
