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+ | This is essentially the same as the example done in class for how many times it would take to get a Heads when fliping a coin. [[cleppane|cleppane]] | ||
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+ | [[Michael Anderson|Michael's Solution]] |
Latest revision as of 20:10, 4 March 2009
for part a: would the probability that a 6 comes up on the nth try be (5/6)^(n-1) *(1/6)? Brandy
That makes sense to me JRHaynie
This is essentially the same as the example done in class for how many times it would take to get a Heads when fliping a coin. cleppane