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I think for part b.) we use Bernoilli trials, so the solution would be found by | I think for part b.) we use Bernoilli trials, so the solution would be found by | ||
(10 choose 0)*(.6^10)*(.4^0) | (10 choose 0)*(.6^10)*(.4^0) | ||
| + | |||
| + | Does anyone understand part C. It's confusing me. --[[User:Krwade|Krwade]] 20:48, 24 February 2009 (UTC) | ||
Revision as of 16:48, 24 February 2009
I think for part b.) we use Bernoilli trials, so the solution would be found by (10 choose 0)*(.6^10)*(.4^0)
Does anyone understand part C. It's confusing me. --Krwade 20:48, 24 February 2009 (UTC)
