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'''[[MA 375 Spring 09 HW 6|Back]]''' | '''[[MA 375 Spring 09 HW 6|Back]]''' | ||
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| + | There are 2^5 possibilities and they are 5 situations where you can have four heads but only one of them has the first one as a tail, so you have 1/32 divided by 1/2 for the probability of having a tail come up on the first toss. This gives you 1/16 which is your answer. | ||
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| + | Hope this helps | ||
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| + | -Brian | ||
Latest revision as of 19:01, 23 February 2009
There are 2^5 possibilities and they are 5 situations where you can have four heads but only one of them has the first one as a tail, so you have 1/32 divided by 1/2 for the probability of having a tail come up on the first toss. This gives you 1/16 which is your answer.
Hope this helps
-Brian
