(New page: Show that <math>\int_{\mathbb{R}^{n}}e^{-|x|^{2}}d\bar{x} = \pi^{n/2}</math> Proof by induction(by Pirate Robert): For <math>n=1</math> it is an easy manipulation of Calculus 2 tricks. (...)
 
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Show that <math>\int_{\mathbb{R}^{n}}e^{-|x|^{2}}d\bar{x} = \pi^{n/2}</math>
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Show that <math>\int_{\mathbb{R}^{n}}e^{-|x|^{2}}d\vec{x} = \pi^{n/2}</math>
  
Proof by induction(by Pirate Robert):
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Proof by induction (by Robert the Pirate):
  
 
For <math>n=1</math> it is an easy manipulation of Calculus 2 tricks. (I really don't feel like writing the whole thing out)
 
For <math>n=1</math> it is an easy manipulation of Calculus 2 tricks. (I really don't feel like writing the whole thing out)
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Now, assume that for <math>n</math> the equation is true. We just need to show that it holds for <math>n+1</math>
 
Now, assume that for <math>n</math> the equation is true. We just need to show that it holds for <math>n+1</math>
  
<math>\int_{\mathbb{R}^{n}}e^{-|x|^{2}}dx_{1}\ldots dx_{n+1}</math>
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<math>\int_{\mathbb{R}^{n+1}}e^{-|x|^{2}}dx_{1}\cdots dx_{n+1}=</math>
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<math>\int_{\mathbb{R}}e^{-x_{n+1}^{2}}(\int_{\mathbb{R}^{n}}e^{-|x|^{2}}dx_{1}\cdots dx_{n})dx_{n+1}</math>
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<math>=\pi^{1/2}\cdot \pi^{n/2} = \pi^{(n+1)/2}</math> (By Fubini's Theorem and properties of exp)
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Q.E.D

Revision as of 09:19, 27 July 2009

Show that $ \int_{\mathbb{R}^{n}}e^{-|x|^{2}}d\vec{x} = \pi^{n/2} $

Proof by induction (by Robert the Pirate):

For $ n=1 $ it is an easy manipulation of Calculus 2 tricks. (I really don't feel like writing the whole thing out)

Now, assume that for $ n $ the equation is true. We just need to show that it holds for $ n+1 $

$ \int_{\mathbb{R}^{n+1}}e^{-|x|^{2}}dx_{1}\cdots dx_{n+1}= $ $ \int_{\mathbb{R}}e^{-x_{n+1}^{2}}(\int_{\mathbb{R}^{n}}e^{-|x|^{2}}dx_{1}\cdots dx_{n})dx_{n+1} $ $ =\pi^{1/2}\cdot \pi^{n/2} = \pi^{(n+1)/2} $ (By Fubini's Theorem and properties of exp)

Q.E.D

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