(References)
(Narrowed the image width slightly.)
 
Line 7: Line 7:
 
<math>w=[w1, w2, w3,...,wd]</math> => weight vector<br>
 
<math>w=[w1, w2, w3,...,wd]</math> => weight vector<br>
 
<math>w_o</math> =>bias or threshold weight<br>
 
<math>w_o</math> =>bias or threshold weight<br>
[[Image:lin_classifier_Old Kiwi.jpg]]
+
[[Image:lin_classifier.jpg _Old Kiwi| 800px]]
  
 
<b>Two-catergory case</b><br>
 
<b>Two-catergory case</b><br>

Latest revision as of 09:12, 7 April 2008

From Duda, Hart & Stock Textbook chapter 5.2


Discriminant fuction that is a linear combination of the component x
$ g(x)=w^Tx +w_o $

$ w=[w1, w2, w3,...,wd] $ => weight vector
$ w_o $ =>bias or threshold weight
800px

Two-catergory case
Decide w1 if $ g(x)>0 =>w^Tx > -wo $
Decide w2 if $ g(x) <0 =>w^Tx < -wo $
If $ g(x)=0 $ then it can we assigned to any class or be left undefined

$ g(x)=0 $ define a decision surface (which is a hyperplane) that separates w1 and w2 points

The hyperplane divides the feature space into two halfs: region R1 for w1 and region R2 for w2
w is normal to any vector laying in the hyperplane

The distance from x to the hyperplane is $ g(x)/||w|| $
The distance from the origin to the hyperplane is $ w_o/||w|| $

Proof:
$ x=xp+r(w/||w||) $

  • xp = normal projectionof x onto hyperplane(H)
  • r = desired algebraic distance - positive if on the positive side and negative if on the negative side

Because $ g(xp) =0 $
$ g(x) =w^Tx + wo =r||w|| $
therefore $ r = g(x)/||w|| $

[Image:decision_bound.jpg]]

Multicategory case

Some ways to devise multicategory classifiers
-reduce the problem to c-1 two-class problems; where teh ith problem is solvd by a linear discriminant function that separates points assigned to w_i from those not assigned to w_i
-use c(c-1)/2 linear discriminants; one for every pair of classes
-defining c linear discriminant functions $ g_i(x)=w^Tx_i+w_{i_o} $ $ i=1,..,c $
assigning x to w_i if $ g_i(x)>g_j(x) {\forall} j !=i $

A linear machine divides the feature space into c decision regions

If Region i and region j are contiguous, the boundary between them is a portion of the hyperplane Hij defined by $ g_i(x)=g_j(x) $ => $ (w_i-w_j)^Tx+(w_{i_o}-w_{j_o})=0 $

$ w_i-w_j $ is normal to Hij
$ (g_i-g_j)/||w_i-w_j|| $ is the distance from x to Hij

References

Duda, Hart, and Stork, Chapter 5, section 5.2

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang