Revision as of 11:24, 8 September 2008 by Mitche23 (Talk)

Independence

In Two Events

$ P(A \bigcap B) = P(A) \times P(B) $

For example, given a coin, are the two outcomes independent?

$ P( \lbrace C_1=H \rbrace \bigcap \lbrace C_2 =H \rbrace ) = 1/4 $

$ P( C_1=H ) \times P(C_2=H) = 1/2 \times 1/2 = 1/4 $

Since the product of the two probabilities is equal to overall probability, the events are independent.

[1]

In Multiple Events

$ \bigcap_i A_i = \prod_i P(A_i) $

For i $ \in $ S

Conditional Probability

A & B are conditionally independent given C if the following formula holds true.

$ P(A \bigcap B|C) = P(A|C) \times P(B|C) $

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Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

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