(New page: <math>\ -e^{\alpha t }u(-t) \leftrightarrow \frac{1}{s + \alpha}</math>)
 
 
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<math>\ -e^{\alpha t }u(-t) \leftrightarrow \frac{1}{s + \alpha}</math>
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<math>\ -e^{\alpha t }u(-t) \leftrightarrow \frac{1}{s + \alpha}</math>, for Re{s} <  <math>\ - \alpha</math>

Latest revision as of 17:25, 24 November 2008

$ \ -e^{\alpha t }u(-t) \leftrightarrow \frac{1}{s + \alpha} $, for Re{s} < $ \ - \alpha $

Alumni Liaison

Meet a recent graduate heading to Sweden for a Postdoctorate.

Christine Berkesch