(New page: <math>\ e^{\alpha t }u(t) \leftrightarrow \frac{1}{s + \alpha}</math>)
 
 
Line 1: Line 1:
<math>\ e^{\alpha t }u(t) \leftrightarrow \frac{1}{s + \alpha}</math>
+
<math>\ e^{\alpha t }u(t) \leftrightarrow \frac{1}{s + \alpha}</math>, for Re{s} >  <math>\ - \alpha</math>

Latest revision as of 17:24, 24 November 2008

$ \ e^{\alpha t }u(t) \leftrightarrow \frac{1}{s + \alpha} $, for Re{s} > $ \ - \alpha $

Alumni Liaison

BSEE 2004, current Ph.D. student researching signal and image processing.

Landis Huffman