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Suppose that f(a)=g(a)=0 and that f and g are differentiable on an open interval <i>I</i> containing a.  Suppose also that g'(x)/=0 on <i>I</i> if x/=a.  Then
 
Suppose that f(a)=g(a)=0 and that f and g are differentiable on an open interval <i>I</i> containing a.  Suppose also that g'(x)/=0 on <i>I</i> if x/=a.  Then
 
<math>
 
<math>
\lim_{x -> a}\frac{f(x)}{g(x)}= \lim_{x-> a}\frac{f'(x)}{g'(x)}
+
\lim_{x \to\ a}\frac{f(x)}{g(x)}= \lim_{x \to\ a}\frac{f'(x)}{g'(x)}
 
</math>,
 
</math>,
 
if the limis on the right exists (or is positive or negative infinity).
 
if the limis on the right exists (or is positive or negative infinity).
  
 
This is Elizabeth's favorite theorem.
 
This is Elizabeth's favorite theorem.
 
 
<math>
 
\displaystyle\lim_{x\to\a}\frac{f(x)}{g(x)}=\displaystyle\lim_{x\to\a}\frac{f'(x)}{g'(x)}
 
</math>,
 

Revision as of 12:41, 4 September 2008

Suppose that f(a)=g(a)=0 and that f and g are differentiable on an open interval I containing a. Suppose also that g'(x)/=0 on I if x/=a. Then $ \lim_{x \to\ a}\frac{f(x)}{g(x)}= \lim_{x \to\ a}\frac{f'(x)}{g'(x)} $, if the limis on the right exists (or is positive or negative infinity).

This is Elizabeth's favorite theorem.

Alumni Liaison

Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett