Difference between revisions of "Krauserece301bonus1" - Rhea

Latest revision as of 13:04, 11 February 2013

Question 1:

linear system: y = x₁(2t) + x₁(t)

nonlinear: y = (x(t)) • (x(t-1))

causal: y = e^t+5x(t-1)

noncausal: y = e^t-5x(t+1)

with memory: y = (x[n-5])^3

memoryless: y = (x[n]) ^ 3

invertible: y(t) = (x(t)) ^ t

uninvertible: y(t) = (sum) k=0 -> 5 kx[n]

stable: y[n] = x[n] ^ x[n]

y[n] = n^2x[n-1]

time variying: y[n] = (n^.5)x[x+1] - 3

time invariant: y[n] = 18x[n+1] - 1047(x[n])^2

@@ Line 1: / Line 1: @@
 [[Category:ECE301Spring2013JVK]] [[Category:ECE]] [[Category:ECE301]] [[Category:Probability]] [[Category:Problem_solving]] [[Category:LTI_systems]] [[Category:Convolution]] [[Category:Period]]
@@ Line 19: / Line 18: @@
 uninvertible: y(t) = (sum) k=0 -&gt; 5 kx[n]
+stable: y[n] = x[n] ^ x[n]
+y[n] = n^2x[n-1]
+time variying: y[n] = (n^.5)x[x+1] - 3
+time invariant: y[n] = 18x[n+1] - 1047(x[n])^2
 [[Bonus_point_1_ECE301_Spring2013|Back to first bonus point opportunity, ECE301 Spring 2013]]