(New page: Here are a couple things i noted from office hours on friday If we were to know Q P[H1] = Q P[H1|Q=q] = q P[H1] = integral from 0 to 1 of P(H1|Q=q)fQ(q)dq = integral from 0 to 1 of q(2q...)
 
 
Line 4: Line 4:
  
 
P[H1] = Q
 
P[H1] = Q
 +
 
P[H1|Q=q] = q
 
P[H1|Q=q] = q
 +
 
P[H1] = integral from 0 to 1 of P(H1|Q=q)fQ(q)dq
 
P[H1] = integral from 0 to 1 of P(H1|Q=q)fQ(q)dq
 +
 
= integral from 0 to 1 of q(2q)dq
 
= integral from 0 to 1 of q(2q)dq

Latest revision as of 09:55, 20 October 2008

Here are a couple things i noted from office hours on friday

If we were to know Q

P[H1] = Q

P[H1|Q=q] = q

P[H1] = integral from 0 to 1 of P(H1|Q=q)fQ(q)dq

= integral from 0 to 1 of q(2q)dq

Alumni Liaison

Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett