(Sinusodial Modulation)
Line 45: Line 45:
  
 
<math>Y(\omega) = \frac{1}{2\pi}(\pi\delta(\omega + \omega_ct)+\pi\delta(\omega - \omega_ct))X(\omega)</math>
 
<math>Y(\omega) = \frac{1}{2\pi}(\pi\delta(\omega + \omega_ct)+\pi\delta(\omega - \omega_ct))X(\omega)</math>
 +
 +
<math>Y(\omega) = \frac{1}{2}(X(\omega + \omega_ct)+X(\omega + \omega_ct))</math>
 +
 +
With this modulation <math>x(t)</math> is being copied and halved, one copy is shifted <math>\omega</math> while the other one is shifted <math>-\omega</math>

Revision as of 17:11, 17 November 2008

How it works

$ x(t)c(t)=y(t) $

Where $ x(t) $ is the "information signal" and $ c(t) $ is the "carrier"


Two Major Carriers

Complex Exponential

$ c(t) = e^{j(\omega_ct+\theta_c)} $

Sinusoidal

$ c(t) = cos(\omega_ct+\theta_c) $

    Where $ \omega_c $ is the frequency and $ \theta_c $ is the phase

Complex Exponential Modulation

$ y(t) = e^{j\omega_ct}x(t) $

$ Y(\omega)=F(e^{j\omega_ct}x(t)) $

$ Y(\omega)=\frac{1}{2\pi}F(e^{j\omega_ct})X(\omega) $

$ Y(\omega)=\frac{1}{2\pi}(2\pi \delta(\omega-\omega_c)X(\omega) $

$ Y(\omega)=X(\omega-\omega_c) $

What happens with this modulation is that the original signal $ x(t) $ and shifted in the frequency domain by $ \omega_c $

Demodulation ie. How the Heck do I get back my original signal

$ y(t)e^{-j\omega_ct}=x(t) $

Sinusodial Modulation

$ y(t) = \cos(\omega_ct)x(t) $

$ Y(\omega) = F(\cos(\omega_ct)x(t)) $

$ Y(\omega) = \frac{1}{2\pi}F(\cos(\omega_ct))F(x(t)) $

$ Y(\omega) = \frac{1}{2\pi}(\pi\delta(\omega + \omega_ct)+\pi\delta(\omega - \omega_ct))X(\omega) $

$ Y(\omega) = \frac{1}{2}(X(\omega + \omega_ct)+X(\omega + \omega_ct)) $

With this modulation $ x(t) $ is being copied and halved, one copy is shifted $ \omega $ while the other one is shifted $ -\omega $

Alumni Liaison

To all math majors: "Mathematics is a wonderfully rich subject."

Dr. Paul Garrett