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111 | 111 | ||
| − | So, the probability that there will be and odd number of 1's occurs when there is either one 1 or three 1's making P(E)=1/2 | + | So, the probability that there will be and odd number of 1's occurs when there is either one 1 or three 1's making P(E)=1/2. |
The probability that the | The probability that the | ||
Revision as of 10:07, 4 March 2009
There are 8 options for bitstrings of length 3 :
000
001
010
100
011
110
101
111
So, the probability that there will be and odd number of 1's occurs when there is either one 1 or three 1's making P(E)=1/2. The probability that the
