Revision as of 16:41, 8 December 2008 by Gutierjm (Talk)

The way I went about this problem is I set Y=X-N and substituted all over the place

So if expanding on the last entry I got

E[X]-E[N] + (E[X(X-N)]-E[X]E[X-N])/(Var(x)) * (X-E[X])

             After some rearranging

E[X]-E[N] +(E[X^2]-E[XN]+E[X]^2+E[X]E[N])/(E[X^2]+E[X]^2] *(X-E[X])

E[X]-E[N] + (E[X^2]-E[X]^2)/(E[X^2]-E[X]^2) *(X-E[X])

E[X]-E[N] + (X-E[X])

Thats what i got so far you sould be able to plug in values assuming this is right..theres an example like in class btw

Do you use law of iterated expectation here?

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