Revision as of 16:40, 8 December 2008 by Gutierjm (Talk)

(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

The way I went about this problem is I set Y=X-N and substituted all over the place

So if expanding on the last entry I got

E[X]-E[N] + (E[X(X-N)]-E[X]E[X-N])/(Var(x) * (X-E[X])

             After some rearranging

E[X]-E[N] +(E[X^2]-E[XN]+E[X]^2+E[X]E[N])/(E[X^2]+E[X]^2] *(X-E[X])

E[X]-E[N] + (E[X^2]-E[X]^2)/(E[X^2]-E[X]^2) *(X-E[X])

E[X]-E[N] + (X-E[X])

Thats what i got so far you sould be able to plug in values assuming this is right..theres an example like in class btw

Do you use law of iterated expectation here?

Alumni Liaison

Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett