(New page: It seems it is this problem is easy enough to write out all the possibilities. poss 1. (5)(0)(0) This stands for all five items in any of the three boxes because they are indistinguis...) |
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It seems it is this problem is easy enough to write out all the possibilities. | It seems it is this problem is easy enough to write out all the possibilities. | ||
| − | poss 1. (5)(0)(0) This stands for all five items in any of the three boxes because they are indistinguishable | + | poss 1. (5)(0)(0) This stands for all five items in any of the three boxes because they are indistinguishable. |
| + | |||
poss 2. (4)(1)(0) This stands for four items in one of the three boxes and the remaining item in one of the remaining two boxes. | poss 2. (4)(1)(0) This stands for four items in one of the three boxes and the remaining item in one of the remaining two boxes. | ||
| − | poss 3. (3)(2)(0) Same reasoning | + | |
| + | poss 3. (3)(2)(0) Same reasoning. | ||
| + | |||
poss 4. (3)(1)(1) | poss 4. (3)(1)(1) | ||
| + | |||
poss 5. (2)(2)(1) | poss 5. (2)(2)(1) | ||
--[[User:Jahlborn|Jahlborn]] 22:34, 28 September 2008 (UTC) | --[[User:Jahlborn|Jahlborn]] 22:34, 28 September 2008 (UTC) | ||
Revision as of 18:35, 28 September 2008
It seems it is this problem is easy enough to write out all the possibilities.
poss 1. (5)(0)(0) This stands for all five items in any of the three boxes because they are indistinguishable.
poss 2. (4)(1)(0) This stands for four items in one of the three boxes and the remaining item in one of the remaining two boxes.
poss 3. (3)(2)(0) Same reasoning.
poss 4. (3)(1)(1)
poss 5. (2)(2)(1)
--Jahlborn 22:34, 28 September 2008 (UTC)
