(New page: By listing the possibilities, we get: 3 + 1 + 1 = 5 2 + 2 + 1 = 5 4 + 1 + 0 = 5 5 + 0 + 0 = 5 3 + 2 + 0 = 5 There are 2 ways if we want all the boxes to have an object, if not there are...)
 
Line 2: Line 2:
  
 
3 + 1 + 1 = 5
 
3 + 1 + 1 = 5
 +
 
2 + 2 + 1 = 5
 
2 + 2 + 1 = 5
 +
  
 
4 + 1 + 0 = 5
 
4 + 1 + 0 = 5
 +
 
5 + 0 + 0 = 5
 
5 + 0 + 0 = 5
 +
 
3 + 2 + 0 = 5
 
3 + 2 + 0 = 5
  
 
There are 2 ways if we want all the boxes to have an object, if not there are 2 + 3 = 5 ways.
 
There are 2 ways if we want all the boxes to have an object, if not there are 2 + 3 = 5 ways.

Revision as of 20:58, 24 September 2008

By listing the possibilities, we get:

3 + 1 + 1 = 5

2 + 2 + 1 = 5


4 + 1 + 0 = 5

5 + 0 + 0 = 5

3 + 2 + 0 = 5

There are 2 ways if we want all the boxes to have an object, if not there are 2 + 3 = 5 ways.

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Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett