Solution to Prob 4.4b
Its given that X(jw) =
$ ~2, ~~0 \le \omega \le 2 $
$ -2, ~~-2 \le \omega < 0 $
$ ~0, ~~|\omega| > 2 $
$ \therefore x(t) = \frac {1}{2\pi} \int_{-\infty}^{\infty} X(j\omega) e^{jt\omega}\,d\omega $
