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<math>\sum_{n=1}^N n = \dfrac12N\left(N+1\right)</math> | <math>\sum_{n=1}^N n = \dfrac12N\left(N+1\right)</math> | ||
| − | <math>\sum_{n=1}^N 1 = N</math> | + | <math>\sum_{n=1}^N n\left(n+1\right) = \dfrac13N\left(N+1\right)\left(N+2\right)</math> |
[[Category:MA181Fall2011Bell]] | [[Category:MA181Fall2011Bell]] | ||
Revision as of 21:39, 3 September 2011
Homework 2 collaboration area
$ \sum_{n=1}^N 1 = N $
$ \sum_{n=1}^N n = \dfrac12N\left(N+1\right) $
$ \sum_{n=1}^N n\left(n+1\right) = \dfrac13N\left(N+1\right)\left(N+2\right) $
