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       <math>X(s)= \frac{1}{s+a}</math>
 
       <math>X(s)= \frac{1}{s+a}</math>
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* [[Homework _ECE301Fall2008mboutin#10 Daniel Morris: Properties of the Region of Convergence(ROC)]]

Revision as of 12:23, 20 November 2008

                             == Fundamentals of Laplace Transform ==
     Let the signal be:
     $ x(t) =e^ {-at} \mathit{u} (t) $
     
     On doin a Laplace Transform
     $ X(s)= \int_{-\infty}^{\infty}x(t){e^{-st}}\, dt $
     $ X(s)= \int_{-\infty}^{\infty}{e^{-at}}{e^{-st}}dt   ,\mathit{u} (t)=1,t>0 $
      $ X(s)= \frac{1}{s+a} $


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