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       <math>x(t) =\e^ (-at)\ \mathit{u}(t)</math>
+
       <math>x(t) =e^(-at) \mathit{u}(t)</math>

Revision as of 11:54, 19 November 2008

                             == Fundamentals of Laplace Transform ==


     $ x(t) =e^(-at) \mathit{u}(t) $

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