(New page: '''Differentiation''' Define a function x(t) with its Fourier transform being X(jw) Then by definition x(t) = <math>\int\limits_{-\infty}^{\infty}X(jw)e^{(-\jmath wt)}dt</math> The der...)
 
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With the key point being made that differentiation and integration are interchangable operations.  The proof of this is not  
 
With the key point being made that differentiation and integration are interchangable operations.  The proof of this is not  
  
difficult however it is time consuming.  The book assumes that summations and integrations can be interchange also,
+
difficult however it is time consuming.  The book assumes that summations and integrations can be interchanged also,
  
 
therefore I will go without proof of the interchangability of differentiation and integration.
 
therefore I will go without proof of the interchangability of differentiation and integration.
  
so '''F'''x(t)' = jwX(jw)
+
so '''F'''(x(t)') = jwX(jw)

Revision as of 01:07, 9 July 2009

Differentiation

Define a function x(t) with its Fourier transform being X(jw)

Then by definition x(t) = $ \int\limits_{-\infty}^{\infty}X(jw)e^{(-\jmath wt)}dt $

The derivative of x(t) equals

= $ \int\limits_{-\infty}^{\infty}jwX(jw)e^{(-\jmath wt)}dt $

With the key point being made that differentiation and integration are interchangable operations. The proof of this is not

difficult however it is time consuming. The book assumes that summations and integrations can be interchanged also,

therefore I will go without proof of the interchangability of differentiation and integration.

so F(x(t)') = jwX(jw)

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Basic linear algebra uncovers and clarifies very important geometry and algebra.

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