(Linear System)
(Example)
 
(4 intermediate revisions by the same user not shown)
Line 4: Line 4:
 
A system is called "Linear"  
 
A system is called "Linear"  
 
if for any constants a,b and for any inputs x1(t),x2(t),(x1[n],x2[n])  
 
if for any constants a,b and for any inputs x1(t),x2(t),(x1[n],x2[n])  
yielding output y1(t),y2(t) respective's the
+
yielding output y1(t),y2(t),respectively, the respond to a*x1(t)+b*x2(t) is a*y1(t)+b*y2(t)
  
 
== Example ==
 
== Example ==
<pre>
+
A)LINEAR
For function y=2t+1, its derivitive y'=2
+
  Let:
y' is a constant
+
    x1(t)=t, x2(t)=2t; 
Thus y=2t+1 is a linear system.
+
    System: y(t)=3*x(t)
 +
    Thus, y1(t)=3t,y2(t)=6t
 +
  So say a,b are any non-zero constant
 +
    a*x1(t)->system->3at
 +
                        +    --->Output= 3at+6bt    -----(1)
 +
    b*x2(t)->system->6bt 
  
  
For function y=sin(t), y'=cos(t)
+
    a*x1(t)+b*x2(t)=at+2bt->system->Output=3*(at+2bt)= 3at+6bt ----------(2)
y' is not a constant
+
Thus y=sin(t) is a non-linear system.
+
  
</pre>
+
    (1)=(2),so linear.
 +
 
 +
B)NON-LINEAR
 +
  Let:
 +
    x1(t)=t, x2(t)=2t; 
 +
    System: y(t)=x(t)^2
 +
    Thus, y1(t)=t^2,y2(t)=4t^2
 +
 
 +
  So say a,b are any non-zero constant
 +
    a*x1(t)->system->a*t^2
 +
                            +    --->Output= a*t^2+4b*t^2    -----(3)
 +
    b*x2(t)->system->b*4t^2
 +
 
 +
    a*x1(t)+b*x2(t)=at+2bt->system->Output=(at+2bt)^2 ----------(4)
 +
 
 +
    (3)!=(4),so non-linear.

Latest revision as of 17:02, 12 September 2008

Linear System

A system is called "Linear" if for any constants a,b and for any inputs x1(t),x2(t),(x1[n],x2[n]) yielding output y1(t),y2(t),respectively, the respond to a*x1(t)+b*x2(t) is a*y1(t)+b*y2(t)

Example

A)LINEAR

 Let:
    x1(t)=t, x2(t)=2t;   
    System: y(t)=3*x(t)
    Thus, y1(t)=3t,y2(t)=6t
 So say a,b are any non-zero constant
    a*x1(t)->system->3at
                       +    --->Output= 3at+6bt     -----(1)
    b*x2(t)->system->6bt  


    a*x1(t)+b*x2(t)=at+2bt->system->Output=3*(at+2bt)= 3at+6bt ----------(2)
    (1)=(2),so linear.

B)NON-LINEAR

 Let:
    x1(t)=t, x2(t)=2t;   
    System: y(t)=x(t)^2
    Thus, y1(t)=t^2,y2(t)=4t^2
 So say a,b are any non-zero constant
    a*x1(t)->system->a*t^2
                           +    --->Output= a*t^2+4b*t^2     -----(3)
    b*x2(t)->system->b*4t^2
    a*x1(t)+b*x2(t)=at+2bt->system->Output=(at+2bt)^2 ----------(4)
    (3)!=(4),so non-linear.

Alumni Liaison

Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett