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Response from Mickey Rhoades [[User:Mrhoade|Mrhoade]]
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Response from Mickey Rhoades [[User:Mrhoade|Mrhoade]]  
  
I thought the same thing. &nbsp;My solution is pretty intense as well. &nbsp;It seems like there is the portion from the initial conditions which is e<sup>-2t</sup> - e<sup>-3t</sup> and then there is the portion from the impulse function which is added beginning at pi/2, e<sup>pi</sup>e<sup>-2t</sup> - e<sup>3pi/2</sup>e<sup>-3t</sup> and then there is the portion of the output due to the cosine input beginning at pi. &nbsp;This section looks like a sin/cos wave inside an exponential envelope. &nbsp;Did anyone else come up with something different? -Mick
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I thought the same thing. &nbsp;My solution is pretty intense as well. &nbsp;It seems like there is the portion from the initial conditions which is e<sup>-2t</sup> - e<sup>-3t</sup> and then there is the portion from the impulse function which is added beginning at pi/2, e<sup>pi</sup>e<sup>-2t</sup> - e<sup>3pi/2</sup>e<sup>-3t</sup> and then there is the portion of the output due to the cosine input beginning at pi. &nbsp;This section looks like a sin/cos wave inside an exponential envelope. &nbsp;Did anyone else come up with something different? -Mick  
  
 
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Remark from [[User:Bell|Steve Bell]]:
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Remark from [[User:Bell|Steve Bell]]:  
  
That's life for engineers. The solution corresponds to a hammer hit at time pi/2 followed by turning on a vibration at time pi. You will note that the solution you get, although piecewise defined, is continuous. The velocity jumps at the hammer hit. After you experience trying to graph it with your bare hands, I will show you how to use maple to graph these things.
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That's life for engineers. The solution corresponds to a hammer hit at time pi/2 followed by turning on a vibration at time pi. You will note that the solution you get, although piecewise defined, is continuous. The velocity jumps at the hammer hit. After you experience trying to graph it with your bare hands, I will show you how to use maple to graph these things.  
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Revision as of 09:36, 14 October 2013

Homework 6 collaboration area


From Mnestero:

On 6.4 prob 10 I am getting a pretty intense solution that is difficult to graph. Am I on the right track? How in depth are we supposed to graph the solution?


Response from Mickey Rhoades Mrhoade

I thought the same thing.  My solution is pretty intense as well.  It seems like there is the portion from the initial conditions which is e-2t - e-3t and then there is the portion from the impulse function which is added beginning at pi/2, epie-2t - e3pi/2e-3t and then there is the portion of the output due to the cosine input beginning at pi.  This section looks like a sin/cos wave inside an exponential envelope.  Did anyone else come up with something different? -Mick


Remark from Steve Bell:

That's life for engineers. The solution corresponds to a hammer hit at time pi/2 followed by turning on a vibration at time pi. You will note that the solution you get, although piecewise defined, is continuous. The velocity jumps at the hammer hit. After you experience trying to graph it with your bare hands, I will show you how to use maple to graph these things.




Back to MA527, Fall 2013

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Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett