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[http://www.math.purdue.edu/~bell/MA425/Lectures/lec10-16.pdf Lecture 10/16/2009] --[[User:Bell|Steve Bell]] | [http://www.math.purdue.edu/~bell/MA425/Lectures/lec10-16.pdf Lecture 10/16/2009] --[[User:Bell|Steve Bell]] | ||
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| + | Professor Bell, You showed in class that we cant evaluate the integral around the curved portion for problem VI.12.2 using the basic estimate because when <math>Theta = Pi/4</math> it turns out to be one. Can we use the basic estimate method for VI.12.1 because now <math>Theta= pi/8</math> which should not cause a problem. Also on your lecture on the 14th when you started problem VI.12.2 the integral over the lower curve, you evaluated it as <math>sqrt(pi)/2</math> shouldn't it be <math>sqrt(pi)/2sqrt(2)</math> ? | ||
| + | --[[User:Kfernan|Kfernan]] 10:05, 20 October 2009 (UTC) | ||
Revision as of 06:05, 20 October 2009
Homework 6
Professor Bell, could you post the notes from friday? Thanks. --Yu Suo 16:31, 18 October 2009 (UTC)
Yu, they are now on the MA 425 Home Page under
Lecture 10/16/2009 --Steve Bell
Professor Bell, You showed in class that we cant evaluate the integral around the curved portion for problem VI.12.2 using the basic estimate because when $ Theta = Pi/4 $ it turns out to be one. Can we use the basic estimate method for VI.12.1 because now $ Theta= pi/8 $ which should not cause a problem. Also on your lecture on the 14th when you started problem VI.12.2 the integral over the lower curve, you evaluated it as $ sqrt(pi)/2 $ shouldn't it be $ sqrt(pi)/2sqrt(2) $ ?
--Kfernan 10:05, 20 October 2009 (UTC)
