Line 9: Line 9:
 
Parametrize the circular part of the boundary via
 
Parametrize the circular part of the boundary via
  
<math>C_r:\quad z(t)=Re^{it}, 0<t<\pi/4.</math>
+
<math>C_R:\quad z(t)=Re^{it}, 0<t<\pi/4.</math>
  
 
You need to show that
 
You need to show that
Line 19: Line 19:
 
<math>|I_R|\le\int_0^{\pi/4} Re^{-R^2\cos(2t)}\,dt</math>
 
<math>|I_R|\le\int_0^{\pi/4} Re^{-R^2\cos(2t)}\,dt</math>
  
and use freshman calculus ideas to show that this integral tends to zero.  (Don't hit it with the big stick, the Lebesgue Dominated Convergence Theorem.)
+
and use freshman calculus ideas to show that this integral tends to zero.  (Don't hit it with the big stick, the Lebesgue Dominated Convergence Theorem.) Hint:  Draw the graph of cos_2t on the interval and realize that the line connecting the endpoints is under the graph.  Compare the integral with what you would get by replacing cos_2t by the simple linear function underneath it.
  
  

Revision as of 10:44, 9 February 2011

Homework 4 discussion area

Problem 7 hint:

$ e^{\pm f(z)} $

Problem 10 hint:

Parametrize the circular part of the boundary via

$ C_R:\quad z(t)=Re^{it}, 0<t<\pi/4. $

You need to show that

$ I_R := \int_{C_R}e^{-z^2}\ dz\to 0 $

as R goes to infinity. You won't be able to use the standard estimate to do this. Write out the definition of the integral to find that

$ |I_R|\le\int_0^{\pi/4} Re^{-R^2\cos(2t)}\,dt $

and use freshman calculus ideas to show that this integral tends to zero. (Don't hit it with the big stick, the Lebesgue Dominated Convergence Theorem.) Hint: Draw the graph of cos_2t on the interval and realize that the line connecting the endpoints is under the graph. Compare the integral with what you would get by replacing cos_2t by the simple linear function underneath it.


Back to the MA 530 Rhea start page

To Rhea Course List

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood