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| + | Hint for IV.6.3 --[[User:Bell|Steve Bell]] | ||
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| + | We assume <math>f''=f</math> on <math>\mathbb C</math>. | ||
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| + | Notice that | ||
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| + | <math>(e^z f)''=e^zf +2e^zf'+e^zf''=2(e^zf + e^zf')=(e^zf)'.</math> | ||
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| + | Let <math>g=e^zf.</math> | ||
Revision as of 04:36, 23 September 2009
Homework 4
Hint for IV.6.3 --Steve Bell
We assume $ f''=f $ on $ \mathbb C $.
Notice that
$ (e^z f)''=e^zf +2e^zf'+e^zf''=2(e^zf + e^zf')=(e^zf)'. $
Let $ g=e^zf. $
