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'''24.'''
 
'''24.'''
 
Did anyone else get the answer to be (1/2^5)/(1/2) = 1/16?
 
Did anyone else get the answer to be (1/2^5)/(1/2) = 1/16?
 +
 +
yes, by using P(E|F)= P(E intersection F)/P(F)
  
  

Revision as of 15:00, 24 February 2010

HW6MA375S10

6.2 - 2, 10, 12, 18, 24, 26, 30

Section 6.2

2.



10. I know d is 1 - answer to c. Any help on c?

Any ideas on part e and/or f?


12.



18. b & c are confusing me. (7 choose n) (1/7)^n, and 7^n are used, but in what form?

If you look at the part of example 13 on pg 410 where they use the pn's this may help you



24. Did anyone else get the answer to be (1/2^5)/(1/2) = 1/16?

yes, by using P(E|F)= P(E intersection F)/P(F)



26.



30. Any hints for part b)? (b) is very similar to (a)

part c) is it just 1/2*1/2^2*1/2^3.....*1/2^10? cause that answer is 2.775E-17 and I don't believe that is a correct solution.

it is a really low number, but it does make sense if you look at the problem


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Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

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