Revision as of 12:50, 16 September 2013 by Rhea (Talk | contribs)

(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Example of Computation of inverse Fourier transform (CT signals)

A practice problem on CT Fourier transform


Let x(t)= $ cos(t) $


Then

$ x(t)=\frac{1}{2\pi}\int_{-\infty}^{\infty}X(\omega)e^{j\omega t}d\omega $

$ x(t)=\frac{1}{2\pi}\int_{-\infty}^{\infty}cos(t)e^{j\omega t}d\omega $

$ x(t)=\frac{1}{2\pi}cos (t)\int_{-\infty}^{\infty}e^{j\omega t}d\omega $

$ x(t)=\frac{1}{2\pi}cos (t){\left.\frac{e^{j\omega t}}{jt}\right]_{-\infty}^{\infty}} $

$ x(t)=\frac{1}{2j\pi t}cos (t){\left.e^{j\omega t}\right]_{-\infty}^{\infty}} $



Back to Practice Problems on CT Fourier transform

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood