(New page: j = <math>\sqrt{-1}</math>)
 
 
(5 intermediate revisions by the same user not shown)
Line 1: Line 1:
j = <math>\sqrt{-1}</math>
+
Euler's identity
 +
 
 +
<math>  e^{j \pi} + 1 = 0, \,\! </math>
 +
 
 +
Euler's formula
 +
 
 +
<math>    e^{jx} = \cos x + j \sin x \,\! </math>
 +
 
 +
<math>        \cos x = \mathrm{Re}\{e^{jx}\} ={e^{jx} + e^{-jx} \over 2}</math>
 +
 
 +
<math>  \sin x = \mathrm{Im}\{e^{jx}\} ={e^{jx} - e^{-jx} \over 2i}.  </math>
 +
 
 +
<math>    \cos(x) = {e^{-jx} + e^{jx} \over 2}</math>
 +
 
 +
<math>    \sin(x) = {e^{-jx} - e^{jx} \over 2j} </math>

Latest revision as of 20:40, 22 July 2009

Euler's identity

$ e^{j \pi} + 1 = 0, \,\! $

Euler's formula

$ e^{jx} = \cos x + j \sin x \,\! $

$ \cos x = \mathrm{Re}\{e^{jx}\} ={e^{jx} + e^{-jx} \over 2} $

$ \sin x = \mathrm{Im}\{e^{jx}\} ={e^{jx} - e^{-jx} \over 2i}. $

$ \cos(x) = {e^{-jx} + e^{jx} \over 2} $

$ \sin(x) = {e^{-jx} - e^{jx} \over 2j} $

Alumni Liaison

Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett