(New page: <math>\ x(t)=\frac{1}{2\pi}\int_{-\infty}^{\infty}\mathcal{X}(\omega)e^{j\omega t}\,d\omega \,</math>) |
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| + | <math>\mathcal{X}(\omega) = \frac{\frac{1}{2j}}{(2 - j4 + jw)^{2}} - \frac{\frac{1}{2j}}{(2 + j4 - jw)^{2}}</math> | ||
| − | <math>\ x(t)=\frac{1}{2\pi}\int_{-\infty}^{\infty}\mathcal{X}(\omega)e^{j\omega t}\,d\omega \,</math> | + | <math>\ x(t)=\frac{1}{2\pi}\int_{-\infty}^{\infty}\mathcal{X}(\omega)e^{j\omega t}\,d\omega </math> |
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| + | <math>= \frac{1}{2\pi}\int_{-\infty}^{\infty}(\frac{\frac{1}{2j}}{(2 - j4 + jw)^{2}} - \frac{\frac{1}{2j}}{(2 + j4 - jw)^{2}})e^{j\omega t}\,d\omega</math> | ||
Revision as of 13:33, 8 October 2008
$ \mathcal{X}(\omega) = \frac{\frac{1}{2j}}{(2 - j4 + jw)^{2}} - \frac{\frac{1}{2j}}{(2 + j4 - jw)^{2}} $
$ \ x(t)=\frac{1}{2\pi}\int_{-\infty}^{\infty}\mathcal{X}(\omega)e^{j\omega t}\,d\omega $
$ = \frac{1}{2\pi}\int_{-\infty}^{\infty}(\frac{\frac{1}{2j}}{(2 - j4 + jw)^{2}} - \frac{\frac{1}{2j}}{(2 + j4 - jw)^{2}})e^{j\omega t}\,d\omega $
