(New page: ==Inverse Fourier Transforms== If we have a Fourier series <math>X(\omega)</math>, then <math>x(t)=\frac{1}{2\pi}\int_{-\infty}^{\infty}X(\omega)e^{j\omega t}d\omega</math> ==Example== <...)
 
 
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[[Category:problem solving]]
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[[Category:Fourier transform]]
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[[Category:inverse Fourier transform]]
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[[Category:signals and systems]]
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== Example of Computation of inverse Fourier transform (CT signals) ==
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A [[CT_Fourier_transform_practice_problems_list|practice problem on CT Fourier transform]]
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==Inverse Fourier Transforms==
 
==Inverse Fourier Transforms==
 
If we have a Fourier series <math>X(\omega)</math>, then
 
If we have a Fourier series <math>X(\omega)</math>, then
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<math>x(t)=4cos(\frac{3\pi}{2}t)</math>
 
<math>x(t)=4cos(\frac{3\pi}{2}t)</math>
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[[CT_Fourier_transform_practice_problems_list|Back to Practice Problems on CT Fourier transform]]

Latest revision as of 12:43, 16 September 2013

Example of Computation of inverse Fourier transform (CT signals)

A practice problem on CT Fourier transform


Inverse Fourier Transforms

If we have a Fourier series $ X(\omega) $, then

$ x(t)=\frac{1}{2\pi}\int_{-\infty}^{\infty}X(\omega)e^{j\omega t}d\omega $

Example

$ X(\omega)=4\pi\delta(\omega-\frac{3\pi}{2})+4\pi\delta(\omega+\frac{3\pi}{2}) $

$ x(t)=\frac{1}{2\pi}\int_{-\infty}^{\infty}4\pi\delta(\omega-\frac{3\pi}{2})e^{j\omega t}+4\pi\delta(\omega+\frac{3\pi}{2})d\omega $

$ x(t)=2\int_{-\infty}^{\infty}\delta(\omega-\frac{3\pi}{2})e^{j\omega t}+delta(\omega+\frac{3\pi}{2})d\omega $

$ x(t)=2e^{j\frac{3\pi}{2}t}+2e^{j\frac{-3\pi}{2}} $

$ x(t)=4[\frac{e^{j\frac{3\pi}{2}t}+e^{-j\frac{3\pi}{2}}}{2}] $

$ x(t)=4cos(\frac{3\pi}{2}t) $


Back to Practice Problems on CT Fourier transform

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BSEE 2004, current Ph.D. student researching signal and image processing.

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