Revision as of 19:02, 8 October 2008 by Ccadwall (Talk)

Inverse Fourier Transform

$ \chi(\omega) = 2 \pi \sigma (\omega - \pi) $

$ x[n] = \frac{1}{2\pi}\int_{-\infty}^{\infty} \delta (\omega - \pi)e^{j\omega t} dw $

$ x[n] = \int_{-\infty}^\infty \delta (\omega - \pi)e^{j\omega t} dw $

Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva