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Let <font size = '4'><math>\chi (w) = \pi \delta (w - 6) - \pi \delta (w - 3)</math></font>
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[[Category:problem solving]]
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[[Category:ECE301]]
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[[Category:ECE]]
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[[Category:Fourier transform]]
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[[Category:inverse Fourier transform]]
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[[Category:signals and systems]]
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== Example of Computation of inverse Fourier transform (CT signals) ==
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A [[CT_Fourier_transform_practice_problems_list|practice problem on CT Fourier transform]]
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----
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Let <font size = '4'><math>\chi (w) = \frac{\pi}{j} 4\delta (w - 6) - \frac{\pi}{j} 4\delta (w + 6)</math></font>
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Then <math>x(t) = \frac{1}{2\pi}\int^{\infty}_{-\infty} \chi (w) e^{jwt}dw</math>
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<math>x(t) = \frac{1}{2\pi} [\frac{4\pi}{j}\int^{\infty}_{-\infty} \delta(w-6)e^{jwt} dw - \frac{4\pi}{j} \int_{-\infty}^{\infty} \delta(w+6)e^{jwt} dw]</math>
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<math>x(t) = \frac{2}{j}e^{j6t} - \frac{2}{j}e^{-j6t} = 4[\frac{e^{j6t} - e^{-j6t}}{2j}] = 4sin(6t)</math>
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----
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[[CT_Fourier_transform_practice_problems_list|Back to Practice Problems on CT Fourier transform]]

Latest revision as of 12:51, 16 September 2013

Example of Computation of inverse Fourier transform (CT signals)

A practice problem on CT Fourier transform


Let $ \chi (w) = \frac{\pi}{j} 4\delta (w - 6) - \frac{\pi}{j} 4\delta (w + 6) $

Then $ x(t) = \frac{1}{2\pi}\int^{\infty}_{-\infty} \chi (w) e^{jwt}dw $

$ x(t) = \frac{1}{2\pi} [\frac{4\pi}{j}\int^{\infty}_{-\infty} \delta(w-6)e^{jwt} dw - \frac{4\pi}{j} \int_{-\infty}^{\infty} \delta(w+6)e^{jwt} dw] $

$ x(t) = \frac{2}{j}e^{j6t} - \frac{2}{j}e^{-j6t} = 4[\frac{e^{j6t} - e^{-j6t}}{2j}] = 4sin(6t) $


Back to Practice Problems on CT Fourier transform

Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva