Revision as of 07:49, 8 October 2008 by Huang122 (Talk)

Let x(t)= $ cos(t) $


Then

$ X(\omega) = \int_{-\infty}^{\infty}x(t)e^{-j\omega t}dt $

$ X(\omega) = \int_{-\infty}^{\infty}cos(t)e^{-j\omega t}dt $

$ X(\omega) = \int_{-\infty}^{\infty}\frac{1}{2}(e^{jt}+e^{-jt})e^{-j\omega t}dt $

$ X(\omega) = \frac{1}{2}(\int_{-\infty}^{\infty}e^{jt(1-\omega}+int_{-\infty}^{\infty}e^{-jt(1+\omega)}) $

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Sees the importance of signal filtering in medical imaging

Dhruv Lamba, BSEE2010