Revision as of 12:17, 7 October 2008 by Anders89 (Talk)

Signal

$ x(t) = e^{3jt}*(u(t+5) - u(t-5)) + e^{-2t}*(u(t+1) - u(t-1))\, $


Transformed

$ X(\omega) = \int_{-\infty}^{\infty}x(t)e^{-j\omega t}dt\, $ $ = \int_{-\infty}^{\infty}e^{3jt}*(u(t+5) - u(t-5))e^{-j\omega t}dt + \int_{-\infty}^{\infty}e^{-2t}*(u(t+1) - u(t-1))e^{-j\omega t}dt\, $

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang