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Integration by Parts
 
Integration by Parts
  
<math>u=t^2 \; \; \; \; \; \; \; \; \; \; \; \; \; \; dv = e^{-j \omega t}</math>
+
<math>u=t^2 \; \; \; \; \; \; \; \; \; \; \; \; \; dv = e^{-j \omega t}</math>
  
 
<math>du=2t dt \; \; \; \; \; \; \; \; v = \frac{1}{-j\omega}e^{-j \omega t}</math>
 
<math>du=2t dt \; \; \; \; \; \; \; \; v = \frac{1}{-j\omega}e^{-j \omega t}</math>

Revision as of 09:42, 3 October 2008

Fourier Transform

$ X(\omega)=\int_{-\infty}^{\infty}x(t)e^{-j\omega t}dt $

$ x(t)=t^2 u(t) $

$ X(\omega)=\int_{-\infty}^{\infty}t^2 u(t) e^{-j\omega t}dt \; = \int_{0}^{\infty}t^2 e^{-j\omega t}dt $

Integration by Parts

$ u=t^2 \; \; \; \; \; \; \; \; \; \; \; \; \; dv = e^{-j \omega t} $

$ du=2t dt \; \; \; \; \; \; \; \; v = \frac{1}{-j\omega}e^{-j \omega t} $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood