(New page: Suppose we have a signal: :<math>e^{-2(t-1)}u(t-1)\,</math> The formula of Fourier Transform is: :<math>X(w) = \int_{-\infty}^{ \infty} x(t)e^{-jwt}dt\,</math> Substituting: :<math>X(...)
(No difference)

Revision as of 15:40, 7 October 2008

Suppose we have a signal:

$ e^{-2(t-1)}u(t-1)\, $

The formula of Fourier Transform is:

$ X(w) = \int_{-\infty}^{ \infty} x(t)e^{-jwt}dt\, $

Substituting:

$ X(w) = \int_{-\infty}^{ \infty} e^{-2(t-1)}u(t-1)e^{-jwt}dt\, $

From the step function, the range becomes 1 to $ \infty $, so the equation becomes:

$ X(w) = \int_{1}^{ \infty} e^{-2(t-1)}e^{-jwt}dt\, $
$ X(w) = \int_{1}^{ \infty} e^{2-(2+jw)t}dt\, $

Integrating yields:

Alumni Liaison

Have a piece of advice for Purdue students? Share it through Rhea!

Alumni Liaison