Revision as of 10:55, 26 September 2008 by Rwijaya (Talk)

Informations

1. $ N = 2\, $

2. $ a_k = 0\, $ for all |k|>1

3. $ \sum_{n=0}^{3}x[n]=2 $

4. $ \sum_{n=0}^{3}(-1)^nx[n]=5 $

Inspections

From first information, we can directly subtitute N into:

$ x[n]=\sum_{n=0}^{3}a_ke^{jk(2\pi/2)n}\, $

$ x[n]=\sum_{n=0}^{3}a_ke^{jk\pi n}\, $

Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva