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From first information, we can directly subtitute N into:
 
From first information, we can directly subtitute N into:
  
<math>x[n]=\sum_{n=0}^{3}a_ke^{jk(2\pi/2)n}</math>
+
<math>x[n]=\sum_{n=0}^{3}a_ke^{jk(2\pi/2)n}\,</math>
 +
 
 +
<math>x[n]=\sum_{n=0}^{3}a_ke^{jk\pi n}\,</math>

Revision as of 10:54, 26 September 2008

Informations

1. $ N = 2\, $

2. $ a_k = 0\, $ for all non-fractional $ k \, $

3. $ \sum_{n=0}^{3}x[n]=2 $

4. $ \sum_{n=0}^{3}(-1)^nx[n]=5 $

Inspections

From first information, we can directly subtitute N into:

$ x[n]=\sum_{n=0}^{3}a_ke^{jk(2\pi/2)n}\, $

$ x[n]=\sum_{n=0}^{3}a_ke^{jk\pi n}\, $

Alumni Liaison

Meet a recent graduate heading to Sweden for a Postdoctorate.

Christine Berkesch