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1. x[n] oscillates between <math> {1 \over 2} and {1 \over -2}</math><br> | 1. x[n] oscillates between <math> {1 \over 2} and {1 \over -2}</math><br> | ||
2. x[0] = 10<br> | 2. x[0] = 10<br> | ||
| − | 3. x[1] = <math> a_0 + {1 \over 2}</math> | + | 3. x[1] = <math> a_0 + {1 \over 2}</math><br> |
4. x[n] has period 2 | 4. x[n] has period 2 | ||
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== Solution == | == Solution == | ||
x[n] = 10 + <math>sin[{\pi \over 2}n] + {1 \over 2}sin[\pi n] </math> | x[n] = 10 + <math>sin[{\pi \over 2}n] + {1 \over 2}sin[\pi n] </math> | ||
Latest revision as of 18:38, 26 September 2008
Preview
This is only a preview; changes have not yet been saved! (????)
Guess ???
1. x[n] oscillates between $ {1 \over 2} and {1 \over -2} $
2. x[0] = 10
3. x[1] = $ a_0 + {1 \over 2} $
4. x[n] has period 2
Solution
x[n] = 10 + $ sin[{\pi \over 2}n] + {1 \over 2}sin[\pi n] $
