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== Guess ??? ==
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1. x[n] oscillates between <math> {1 \over 2} and {1 \over -2}</math><br>
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2. x[0] = 10<br>
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3. x[1] = <math> a_0 + {1 \over 2}</math>
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4. x[n] has period 2
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== Solution ==
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x[n] = 10 + <math>sin[{\pi \over 2}n] + {1 \over 2}sin[\pi n] </math>

Revision as of 18:38, 26 September 2008

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Guess ???

1. x[n] oscillates between $ {1 \over 2} and {1 \over -2} $
2. x[0] = 10
3. x[1] = $ a_0 + {1 \over 2} $ 4. x[n] has period 2

Solution

x[n] = 10 + $ sin[{\pi \over 2}n] + {1 \over 2}sin[\pi n] $

Alumni Liaison

Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett