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==Solution== | ==Solution== | ||
| − | + | Problem shown worked by steps from above: | |
| − | + | 1. | |
| + | |||
| + | The answer is: <math>{1 \over 2}\sin({\pi \over 4}t)</math> | ||
Revision as of 17:58, 25 September 2008
Homework 4 Ben Horst: 4.1 :: 4.3 :: 4.5
Problem
1. The signal has only two non-zero Fourier coefficients (-1 and 1).
2. The fundamental period of the signal is 8.
3. The function is sinusoidal.
4. Both Fourier coefficients are non-real.
5. The signal has a maximum value of 0.5 and a minimum of -0.5.
Solution
Problem shown worked by steps from above:
1.
The answer is: $ {1 \over 2}\sin({\pi \over 4}t) $
