(h[n] and H(z))
(h[n] and H(z))
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<br>
 
<br>
  
<math> \,\ H[z] = \sum_{m=-\infty}^\infty h[m] * Z</math><sup>(<math>-m</math>)</sup><br>
+
<math> \,\ H[z] = \sum_{m=-\infty}^\infty h[m] * Z</math><sup>(<math>-m</math>)</sup><br><br>
 
<math> \,\ H[z] = \sum_{m=-6}^{5}Z</math><sup>(<math>-m</math>)</sup>
 
<math> \,\ H[z] = \sum_{m=-6}^{5}Z</math><sup>(<math>-m</math>)</sup>

Revision as of 16:19, 25 September 2008

Define a DT LTI System

$ \,\ x[n] = 5*u[n-5] + 6*u[n+6] $

h[n] and H(z)



We obtain $ h[n] $ by finding the response of $ x[n] $ to the unit impulse response ($ \delta[n] $).

$ \,\ h[n] = 5*\delta[n-5] + 6*\delta[n+6] $

$ \,\ H[z] = \sum_{m=-\infty}^\infty h[m] * Z $($ -m $)

$ \,\ H[z] = \sum_{m=-6}^{5}Z $($ -m $)

Alumni Liaison

Questions/answers with a recent ECE grad

Ryne Rayburn